2(^-5x)+^(4x-1)=2(3x+4)

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Solution for 2(^-5x)+^(4x-1)=2(3x+4) equation: 



2(^-5x)+^(4x-1)=2(3x+4)

We move all terms to the left:

2(^-5x)+^(4x-1)-(2(3x+4))=0

We multiply parentheses

-10x+^(4x-1)-(2(3x+4))+=0



We calculate terms in parentheses: -(2(3x+4)), so:

2(3x+4)

We multiply parentheses

6x+8

Back to the equation:

-(6x+8)



We add all the numbers together, and all the variables

-10x+^(4x-1)-(6x+8)=0

We get rid of parentheses

-10x+^(4x-1)-6x-8=0

We add all the numbers together, and all the variables

-16x+^(4x-1)-8=0

We move all terms containing x to the left, all other terms to the right

-16x+^(4x-1)=8

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